Updated EXIN Questions Ensure Thorough CDCS Exam Preparation
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EXIN CDCS Exam Syllabus Topics:
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EXIN EPI Certified Data Centre Specialist Sample Questions (Q117-Q122):
NEW QUESTION # 117
What is the minimum requirement for the power feeds to the building for a Rated-3 data center based on the ANSI/TIA-942 standard?
- A. Two feeds coming from two different substations, one power company is not acceptable
- B. One feed from one substation split over two separated distribution boards in separate rooms
- C. Two feeds coming from two different substations, one power company is acceptable
- D. Two feeds entering the data center building from one substation
Answer: C
Explanation:
The minimum requirement for power feeds to a Rated-3 data center according to ANSI/TIA-942 is to have two independent power feeds, which can come from two different substations provided by the same power company. This ensures redundancy and concurrent maintainability, as each feed can support the load independently during maintenance or failure of the other.
Detailed Explanation:
The separation by two substations ensures resilience in case of a localized outage or substation maintenance, aligning with Rated-3 requirements for uninterrupted operation. ANSI/TIA-942 permits these feeds from a single utility provider as long as they are supplied from distinct substations.
EPI Data Center Specialist References:
EPI underscores the importance of dual power feeds from separate substations for Rated-3 facilities, highlighting that the ability to draw from different substations aligns with redundancy requirements for high availability.
NEW QUESTION # 118
EMF shielding material needs to be installed as EMF levels from the transformer room into the computer room are measured at 100 mG. The transformer room is ~10 meters away, separated by a corridor. Where should shielding be installed?
- A. It does not matter; either close to the transformer room or computer room is okay
- B. Shielding is not required as 100 mG is within acceptable levels
- C. As close as possible to the computer room
- D. As close as possible to the transformer room
Answer: D
Explanation:
The most effective EMF mitigation is to install shielding as close as possible to the source of radiation. By blocking or redirecting magnetic flux at the origin (the transformer room walls), the overall field propagation into adjacent areas is minimized. If shielding were placed at the computer room, the field would already have spread over the intervening space, requiring more material and higher cost.
Standards such as IEEE Std 299 (EMC Shielding Effectiveness) and IEC 61000 emphasize source-based mitigation. Additionally, ANSI/TIA-942 requires EMF shielding where magnetic flux exceeds recommended ICT thresholds (generally <5 mG for sensitive tape/disk storage).
Although 100 mG is often tolerated by modern equipment, legacy magnetic storage can be affected, so shielding is still prudent. Hence, the correct location is at the transformer room wall.
References: IEEE Std 299 (EMI Shielding), ANSI/TIA-942-B §6.6.4 (EMF Requirements), IEC 61000 EMC standards.
NEW QUESTION # 119
How is the PUE ratio calculated?
- A. Total Air Conditioner Input Power ÷ Total Air Conditioner Output Power
- B. Total Facility Power ÷ Total ICT Equipment Power
- C. Total UPS Input Power ÷ Total UPS Output Power
- D. Total ICT Equipment Power ÷ Total Facility Power
Answer: B
Explanation:
PUE (Power Usage Effectiveness) is the most widely used metric to evaluate the energy efficiency of data centers. Defined by The Green Grid and adopted in ISO/IEC 30134-2, PUE is the ratio of the total facility power to the ICT (IT load) power.
Formula:
* Total Facility Power includes all electrical consumption: IT, cooling, lighting, power distribution losses, UPS inefficiency, etc.
* ICT Equipment Power is only the load drawn by servers, storage, and networking gear.
An ideal PUE is 1.0, meaning all power is used by ICT equipment with no overhead. Typical enterprise values are 1.5-2.0, while hyperscale operators target <1.2.
Other options are incorrect:
* B represents the inverse metric, known as DCiE (Data Center infrastructure Efficiency).
* C and D are partial subsystem efficiency metrics, not the global PUE.
References: ISO/IEC 30134-2 (KPIs - PUE), The Green Grid White Paper #49, ANSI/TIA-942-B §7.3.
NEW QUESTION # 120
Do you need to consider bullet (ballistic) protection when designing a data center?
- A. Yes, bullet protection is a requirement of ANSI/TIA-942 for Rated-3/4 data centers
- B. No; bullet protection is not a requirement of ANSI/TIA-942
- C. No, there is no reason for implementing bullet protection as you cannot predict the type of weapons that might be used
- D. Yes, but only when the data center is built in an area with a high criminality rate or with a risk of terrorist attacks
Answer: D
Explanation:
ANSI/TIA-942 requires a risk assessment-based approach to physical security; ballistic protection is not mandated but may be justified by threat analysis.
* A is incomplete (it may still be required by risk).
References: ANSI/TIA-942-B §6.4 Physical Security (threat/risk assessment), ISO 31000 (risk management).
NEW QUESTION # 121
You are allowed to use a calculator for this question.
A computer room has a net volume of approximately 2,500 m³ / 88,287 ft³.
The temperature is 20 °C / 68 °F.
The required design concentration is 7%.
The S-Factor is 0.1359 (metric) / 1.885 (imperial).
Calculate the amount of gas required for this computer room based on FM200. What is the correct weight?
- A. Approximately 410 kg / 900 lbs
- B. Approximately 1,390 kg / 3,000 lbs
- C. Approximately 1,640 kg / 3,600 lbs
- D. Approximately 820 kg / 1,800 lbs
Answer: D
Explanation:
The amount of FM200 gas required can be calculated using the formula:
Weight of Gas=Net Volume×Design Concentration×S-Factor ext{Weight of Gas} = ext{Net Volume}
imes ext{Design Concentration} imes ext{S-Factor}
Weight of Gas=Net Volume×Design Concentration×S-Factor
Using metric units:
* Net Volume: 2,500 m³
* Design Concentration: 7% (or 0.07)
* S-Factor: 0.1359
Calculation:
2,500 m3×0.07×0.1359=821.325 kg2,500 , ext{m}
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